View Full Version : Hat contest - enter before Nov 10, 2013
drake
11-02-2013, 01:49 PM
Just post in this thread to enter.
I'll post info on how the winner is picked. I'll use the results from some pick three lottery system published online to calculate.
Percidae_Papermouth
11-02-2013, 07:29 PM
Bennett, ' Perc P'
Crappie predator
11-04-2013, 04:47 AM
Yaba daba doooo!
www.crappiepredator.com
GrnTmbrHntr
11-04-2013, 06:36 AM
I'm in on this
kswaterfowler
11-04-2013, 04:21 PM
Throw my name in the hat.
Greenhead
11-04-2013, 09:37 PM
I'm in.....
drake
11-05-2013, 07:32 AM
Just post in this thread to enter.
I'll post info on how the winner is picked. I'll use the results from some pick three lottery system published online to calculate.
I'll use the Wisconsin pick 3 from Nov 11, 2013. The order you posted will be your number; replies such as this, are not entries of course. I'll divide the lottery number by number of entries and the remainder will decide the winner. So if the pick 3 is 456 and we have 15 entries the winner would be the 6th entry. 456/15 = 30 r 6
I'm fully expecting comments about over-engineering. ;)
GrnTmbrHntr
11-05-2013, 10:16 AM
All of that would be much easier than just drawing a number out of a hat!!! :D :D
Who's supplying the hat to draw the numbers out of?
drake
11-11-2013, 07:48 PM
There were 6 entries. In order:
0: Percidae_Papermouth
1: Crappie predator
2: GrnTmbrHntr
3: kswaterfowler
4: Greenhead
5: RCC
The lottery result was 102, so 102/6 = 17 r 0
Congrats Percidae_Papermouth!
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